(t/(t-5))^2-(2t)/(t-5)-8=0

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Solution for (t/(t-5))^2-(2t)/(t-5)-8=0 equation:


D( t )

t-5 = 0

t-5 = 0

t-5 = 0

t-5 = 0 // + 5

t = 5

t in (-oo:5) U (5:+oo)

(t/(t-5))^2-((2*t)/(t-5))-8 = 0

(t/(t-5))^2-2*t*(t-5)^-1-8 = 0

(t^2)/((t-5)^2)+(-2*t)/(t-5)-8 = 0

(t^2)/((t-5)^2)+(-2*t*(t-5))/((t-5)^2)+(-8*(t-5)^2)/((t-5)^2) = 0

t^2-2*t*(t-5)-8*(t-5)^2 = 0

10*t-t^2-8*t^2+80*t-200 = 0

90*t-9*t^2-200 = 0

90*t-9*t^2-200 = 0

90*t-9*t^2-200 = 0

DELTA = 90^2-(-200*(-9)*4)

DELTA = 900

DELTA > 0

t = (900^(1/2)-90)/(-9*2) or t = (-900^(1/2)-90)/(-9*2)

t = 10/3 or t = 20/3

(t-10/3)*(t-20/3) = 0

((t-10/3)*(t-20/3))/((t-5)^2) = 0

((t-10/3)*(t-20/3))/((t-5)^2) = 0 // * (t-5)^2

(t-10/3)*(t-20/3) = 0

( t-10/3 )

t-10/3 = 0 // + 10/3

t = 10/3

( t-20/3 )

t-20/3 = 0 // + 20/3

t = 20/3

t in { 10/3, 20/3 }

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